MATH 107 University of Maryland Baltimore County College Wk 5 Algebra Worksheet

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Mathematics

Math 107

University of Maryland - Baltimore County

MATH

Question Description

I need an explanation for this Algebra question to help me study.


01)   

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Week 5 Discussion Problems Identify any domain restrictions, the solve the rational polynomial equation. Check your work to verify your answers. 01) 02) 𝑥 2 −4 2𝑥 2 +3𝑥−2 =1 𝑥+1 𝑥+4 + 𝑥−1 𝑥+2 𝑥 2 +𝑥+1 = 𝑥 2 +𝑥−2 For the given polynomial function, a) State the leading term, leading coefficient, a, and degree, n. b) Describe the end behavior. c) Find the zeros and the multiplicity, m, of each. State whether the graph will cross the x-axis or rebound at each of the zeros. d) Create a sign chart by using test points for each interval. 03) 𝑓(𝑥) = 𝑥 2 (𝑥 − 3) 04) 𝑓(𝑥) = (𝑥 − 1)(𝑥 + 2)2 05) 𝑓(𝑥) = 2𝑥(𝑥 + 1)2 06) 𝑓(𝑥) = (𝑥 2 + 1)(3 − 𝑥) 07) 𝑓(𝑥) = (3𝑥 − 1)(𝑥 + 3)(𝑥 − 3) 08) 𝑓(𝑥) = 𝑥(2𝑥 − 1)2 (𝑥 − 3) 09) 𝑓(𝑥) = −2𝑥 4 (𝑥 − 1)2 10) 𝑓(𝑥) = (2𝑥 + 1)(𝑥 + 1)(𝑥 − 2)(2𝑥 − 1) Solve the rational inequality. Express your answer using interval notation. 11) 2𝑥 2 −𝑥−1 𝑥 2 −9 12) 3𝑥 2 −𝑥−2 3𝑥 2 +5𝑥+2 13) 4𝑥 2 −1 𝑥 2 +𝑥−6 14) 𝑥 2 −𝑥−2 𝑥 2 −6𝑥+8 0 ≤0
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Explanation & Answer

View attached explanation and answer. Let me know if you have any questions.Hello again! Though the original post has the first one only, I have here the works for both problems highlighted with yellow. 😉 As usual, the two files are the answers in two formats (PDF and docx) while the other is for some of the formulas and concepts used. Let me mark this as complete now. For any questions, concerns, clarifications, just send me a message here. 😊

Concepts and Formulas Used


Domain of Rational Functions
𝑅(𝑥) =



𝑝(𝑥)
, 𝑞(𝑥) ≠ 0
𝑞(𝑥)

Difference of Two Square Formula
𝑎2 − 𝑏 2 = (𝑎 + 𝑏)(𝑎 − 𝑏)


Identify any domain restrictions, the solve the rational polynomial equation. Check your work to verify your answers.
01)
02)

𝑥 2 −4
2𝑥 2 +3𝑥−2
𝑥+1
𝑥+2

+

=1

𝑥+4
𝑥−1

=

𝑥 2 +𝑥+1
𝑥 2 +𝑥−2

Solution:
01)

𝑥 2 −4
2𝑥 2 +3𝑥−2

=1

Domain restrictions:
Denominator cannot be equal to 0.
2𝑥 2 + 3𝑥 − 2 ≠ 0
(2𝑥 2 − 𝑥) + (4𝑥 − 2) ≠ 0
𝑥(2𝑥 − 1) + 2(2𝑥 − 1) ≠ 0
(2𝑥 − 1)(𝑥 + 2) ≠ 0
2𝑥 − 1 ≠ 0, 𝑥 + 2 ≠ 0

2𝑥 − 1 ≠ 0
2𝑥 − 1 + 1 ≠ 0 + 1
2𝑥 ≠ 1
2𝑥 1

2
2
𝑥≠

1
2

𝑥+2≠0
𝑥+2−2≠0−2
𝑥 ≠ −2
𝟏

𝟏

𝟐

𝟐

Domain: (−∞, −𝟐) ∪ (−𝟐, ) ∪ ( , ∞)
Solving the equation:
𝑥2 − 4
=1
2𝑥 2 + 3𝑥 − 2
Factoring 𝑥 2 − 4
𝑎2 − 𝑏 2 = (𝑎 + 𝑏)(𝑎 − 𝑏)
𝑥 2 − 4 = (𝑥 + 2)(𝑥 − 2)
In factored form
(𝑥 + 2)(𝑥 − 2)
=1
(2𝑥 − 1)(𝑥 + 2)

Cancel the ...

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