( (x^−3 y^2)/5 ) ^−4

label Algebra
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schedule 1 Day
account_balance_wallet $5

x3y2
5
4
 

 How to solve?
Jan 14th, 2015

( (x^−3 y^2)/5 ) ^−4


((1/x^3)*(y^2)/5)^-4
= (y^2/(5x^3))^-4
=(5x^3/y^2)^4
=625x^12/y^8



Jan 14th, 2015

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