For the reaction For the reaction

Chemistry
Tutor: None Selected Time limit: 1 Day

For the reaction

2C6H6(g) + 15O2(g) Á 12CO2(g) + 6H2O(g)

the expression for the equilibrium constant, K, is

Jan 16th, 2015

I showed to you once before how to get the equilibrium constant, right? If you have the equation 

aA + bB <---> cC + dD 

where A and B are the reactants, C and D are the products, and a,b,c and d are the stoichiometric coefficients (the numbers in front of the compounds) 

The equilibrium constant (Kc) is the concentration of the products divided by the concentration of the reactants or can be written as: 

Kc = [C]^c [D]^d / [A]^a [B]^b 

And remember, solid is never included in getting the constant. Only liquid and gases are included. 

You have the reaction: 

2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g) 

All of them are in gas phase, so they are included in the Kc 

So the expression is: 

Kc = [CO2]^12 [H2O]^6 / [C6H6]^2 [O2]^15


Jan 17th, 2015

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Jan 16th, 2015
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