For the reaction
2C6H6(g) + 15O2(g) Á 12CO2(g) + 6H2O(g)
the expression for the equilibrium constant, K, is
I showed to you once before how to get the equilibrium constant, right? If you have the equation
aA + bB <---> cC + dD
where A and B are the reactants, C and D are the products, and a,b,c and d are the stoichiometric coefficients (the numbers in front of the compounds)
The equilibrium constant (Kc) is the concentration of the products divided by the concentration of the reactants or can be written as:
Kc = [C]^c [D]^d / [A]^a [B]^b
And remember, solid is never included in getting the constant. Only liquid and gases are included.
You have the reaction:
2C6H6(g) + 15O2(g) = 12CO2(g) + 6H2O(g)
All of them are in gas phase, so they are included in the Kc
So the expression is:
Kc = [CO2]^12 [H2O]^6 / [C6H6]^2 [O2]^15
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