 # Circuit Lab, engineering homework help Anonymous
timer Asked: Mar 27th, 2017
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### Question Description

I need to get help with my circuit lab report. I will but all the requirements that you need.

Also, you have to focus on the values because we changed R1, R2 and R3 all to 2 K ohm's. also, the volt values in table 1 we changed it.

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leonelmarquez16
School: Rice University   Look at the document, it has the calculations of the superposition activity, besides the analysis of the equivalent circuit of Thevenin and the graphs of current and voltage.

MORGAN STATE UNIVERSITY DEPARTMENT OF ELECTRICAL AND
COMPUTER ENGINEERING EEGR 203: INTRODUCTION TO
ELECTRICAL LABORATORY Instructor: Dr. Gregory M. Wilkins Lab
4: Superposition Principle and Thevenin’s Theorem
Lab Procedure (Superposition):

PART A

12𝑉 = 2𝐾𝐼1 + 2𝐾(𝐼1 − 𝐼2)

(1)

−3𝑉 = 2𝐾(𝐼2 − 𝐼1) + 2𝐾𝐼2

(2)

12𝑉 = 2𝐾𝐼1 + 2𝐾𝐼1 − 2𝐾𝐼2
12𝑉 = 4𝐾𝐼1 − 2𝐾𝐼2

𝐼1 =

12𝑉 + 2𝐾𝐼2
4𝐾

−3𝑉 = 2𝐾𝐼2 − 2𝐾𝐼1 + 2𝐾𝐼1
2𝐾𝐼1 = 4𝐾𝐼2 + 3𝑉
𝐼1 =

4𝐾𝐼2 + 3𝑉
2𝐾

12𝑉 + 2𝐾𝐼2 4𝐾𝐼2 + 3𝑉
=
4𝐾
2𝐾
12𝑉 + 2𝐾𝐼2 = 2(4𝐾𝐼2 + 3𝑉)
12𝑉 + 2𝐾𝐼2 = 8𝐾𝐼2 + 6𝑉
12𝑉 − 6𝑉 = 8𝐾𝐼2 − 2𝐾𝐼2
6𝑉 = 6𝐾𝐼2
𝐼2 =

6𝑉
6𝐾

𝐼2 = 1𝑚𝐴
𝐼1 =

12𝑉 + 2𝐾(1𝑚𝐴)
= 3.5𝑚𝐴
4𝐾

𝐼𝑅1 = 3.5𝑚𝐴
𝐼𝑅2 = 2.5𝑚𝐴
𝐼𝑅3 = 1𝑚𝐴
𝑉𝑅1 = 3.5𝑚𝐴 ∗ 2𝐾 = 7𝑉
𝑉𝑅2 = 2.5𝑚𝐴 ∗ 2𝐾 = 5𝑉
𝑉𝑅3 = 1𝑚𝐴 ∗ 2𝑘 = 2𝑉

PART B

−3𝑉 = 2𝐾(𝐼2 − 𝐼1) + 2𝐾𝐼2

(1)

2𝐾𝐼1 − 2𝐾𝐼2 + 2𝐾𝐼1 = 0

(2)

4𝐾𝐼1 − 2𝐾𝐼2 = 0
4𝐾𝐼1 = 2𝐾𝐼2
2𝐼1 = 𝐼2

−3𝑉 = 2𝐾(2𝐼1) − 2𝐾𝐼1 + 2𝐾(2𝐼1)
−3𝑉 = 4𝐾𝐼1 − 2𝐾𝐼1 + 4𝐾𝐼1
−3𝑉 = 8𝐾𝐼1 − 2𝐾𝐼1
−3𝑉 = 6𝐾𝐼1
𝐼1 = −0.5𝑚𝐴
𝐼2 = −1𝑚𝐴

𝐼𝑅1 = −0.5𝑚𝐴
𝐼𝑅2 = −0.5𝑚𝐴
𝐼𝑅3 = −1𝑚𝐴
𝑉𝑅1 = −0.5𝑚𝐴 ∗ 2𝐾 = −1𝑉
𝑉𝑅2 = −0.5𝑚𝐴 ∗ 2𝐾 = −1𝑉
𝑉�...

flag Report DMCA  Review Anonymous
Tutor went the extra mile to help me with this essay. Citations were a bit shaky but I appreciated how well he handled APA styles and how ok he was to change them even though I didnt specify. Got a B+ which is believable and acceptable. Brown University

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