If 3.75 mol of K(s) are available, how many moles of H₂(g) are produced if the reaction is run to completion? 2K(s) + 2H₂O(l) → 2KOH(s) + H₂(g)
2 moles of K will produce 1 mole of H2
3.75 mol of k will yield 1.875 mole of H2
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