i need help with problems 28 and 29. please include all work in the answers. here is a pic of the problems

http://imgur.com/KqTus5c

thanks in advance

-(9-x) /(3-√x)= -(3-√x) (3+√x)/ (3-√x) = -(3+√x)

Lim -(3+√x) as x->3 is –(3+√3)

Answer: –(3+√3)

29.

(x^{2}+4x+x+4)/(X+1)^{2} = (x(x+4)+1(x+4))/(x+1)^{2} = (x+4)(x+1)/(x+1)^{2} = (x+4)/(x+1)

As x - > -1 Numerator tends to 3 denominator tends to 0 and so the limit is infinite

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