i need help with problems 28 and 29. please include all work in the answers. here is a pic of the problems
thanks in advance
-(9-x) /(3-√x)= -(3-√x) (3+√x)/ (3-√x) = -(3+√x)
Lim -(3+√x) as x->3 is –(3+√3)
(x(x+4)+1(x+4))/(x+1)2 = (x+4)(x+1)/(x+1)2 = (x+4)/(x+1)
As x - > -1 Numerator tends to 3 denominator tends to 0
and so the limit is infinite
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