= (x2-2x-3x-6)= x(x-2)-3(x-2) = (x-2)(x-3) This is continuous over
the interval (-5,5) though the function becomes 0 at x=2 or x=3. But the
function is quadratic function and so is continuous
is continuous at all points other than 0 . At 0 the function is not defined.
Left limit is –infinity and right limit is +infinity
Jan 19th, 2015
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