A ball is thrown horizontally from the room of a building 9.0 m tall and lands 9.5 m from the base. What was the ball's initial speed?
time it takes to hit the ground can be calculated from,h=1/2 g t^2
, where, h is height of the building 9 m, g is gravitaional accelaration 9,8 m/sec^2 9=1/2* 9.8 t^2 or, t^2 = 9*2/9.8 or, t^2 =1.837or, t = sqrt (1.837) =1.36 secs
so, initial velocity = horizontal distance/time = 9.5/1.36 m/s = 6.985 m/sPlease appreciate by help by selecting my answer as the best, I will help you further. Thanks! :)
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