solve for a d2ca = b4c3a2

Algebra
Tutor: None Selected Time limit: 1 Day

d2ca = b4c3a2

Jan 20th, 2015

d2= b4c2 a

a = d2 /(b4 c2)


Jan 20th, 2015

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Jan 20th, 2015
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Jan 20th, 2015
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