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What volume will 135 grams of butane occupy at 745 torr and 35 degrees celcius?

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What volume will 135 grams of butane occupy at 745 torr and 35 degrees celcius?
Jan 20th, 2015

C4H10 has an ideal molecular weight of 4 x 12 (ideal atomic weight of carbon = 12 due to 6 protons and 6 neutrons) + 10 x 1 (ideal atomic weight of hydrogen = 1 due to 1 proton) = 48 + 10 = 58. 

[Actually, due to statistical isotope distribution, (see:  http://www.convertunits.com/from/grams+butane/to/moles ), the actual value is 58.1222, but for the sake of this problem we’ll use 58.]

We note that 135 grams of butane is 135/58 = 2.328 moles.

Since Volume is inversely proportional to Pressure and directionally proportional to absolute (Kelvin) Temperature:

Volume = 2.328 moles x 22.4 liters {STP, standard temperature and pressure—760 torr and 273.15 deg.K} / mole x (760 torr {STP} / 745 torr) x (308.15 deg.K {35 deg.C} / 273.15 deg.K {STP} ) = 60.0 liters


Jan 21st, 2015

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