At 350 K, Kc = 0.142 for the reaction
2 BrCl(g) ⇀↽ Br2(g) + Cl2(g)
An equilibrium mixture at this temperature
contains equal concentrations of bromine and
chlorine, 0.063 mol/L. What is the equilibrium
concentration of BrCl?
Answer in units of M.
Ke = [Br2]*[Cl2] /
[BrCl]2 = 0.142
0.142/39.69x10-4 = 35.7773
[BrCl] = √35.7773=
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