3 MgCl2 + 2 Al → 3 Mg + 2 AlCl3
c. If 8.00 moles of magnesium chloride react with enough aluminum, how many moles
of aluminum chloride are produced?(Show your work)
d. How many moles of magnesium chloride are needed to with 10.00 moles of
the ratio of magnesium chloride to the produced aluminium chloride is 3:2
hence if 3 is to 8 moles, then
moles of AlCl = (2*8)/3 = 5.33 moles
d. moles of MgCl =(3*10) / 2 = 15 moles
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