find the coordinates of the vertices formed by the system of inequalities.

x + y ≤ 9

x - 2y ≤ 12

3y ≤ 2x + 3

A. (-6,-9), (10,-1), (7,2)

B. (-9,-6), (-1,10), (7,2)

C. (-30,-21), (-6,-9,), (6,15)

D. (-6,-9), (6,-3), (-12,-21)

x + y <= 9, equation 1

x - 2y <= 12, equation 2

1. Subtract second equation from first equation

0x + 3y <= -3

3y >= -3

y >= -1

2. Substitute -1 in for y in second equation

x - 2(-1) <= 12

x + 2 <= 12

x <= 10

So one pair is (10,-1)

So the coordinates in group "A" would satisfy the equations. You can double check all three coordinates if you like in all 3 equations to double check.

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