A mixture consisting of 1 mol of H2O(g) and
1 mol CO(g) is placed in a 8 L reaction vessel
at 800 K. At equilibrium, 0.361 mol CO2(g)
is present as a result of the reaction
CO(g) + H2O(g) ⇀↽ CO2(g) + H2(g).
What is Kc at 800 K?
1-0.361=0.639 mole of CO and H2O are left, and 0.361 mole of H2 is present
Kc = (0.361/8)^2/(0.639/8)^2 = 0.3192
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