x^3y^4 - 27y^4

x^3y^4 - 27y^4= y^4(x^3 -27) =y^4(x^3 -3^3)since a^3 - b^3 =(a-b) (a^2+ab+b^2)so, y^4(x^3 -3^3) = y^4(x-3)(x^2+3x+9)Please appreciate my help, by selecting my answer as the best, Thanks!

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