How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation

maximum height occur at t = v0/32

-V0^2/64 +V0^2/32 = 49

V0^2/64 = 49

V0 = 7*8 = 56 ft/s

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up