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How fast would a ball have to be thrown upward to reach a maximum height of 49 f

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How fast would a ball have to be thrown upward to reach a maximum height of 49 ft? [Hint: Use the discriminant of the equation 

16t2 − v0t + h = 0.
]
 ft/s
Jan 26th, 2015

maximum height occur at t = v0/32 

-V0^2/64 +V0^2/32 = 49

V0^2/64 = 49 

V0 = 7*8 = 56 ft/s 

Jan 26th, 2015

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Jan 26th, 2015
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Jan 26th, 2015
Jun 28th, 2017
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