Time remaining:
The radius of a iron atom is 124 pm. How many iron atoms would have to be laid s

label Chemistry
account_circle Unassigned
schedule 0 Hours
account_balance_wallet $5

The radius of a iron atom is 124 pm. How many iron atoms would have to be laid side by side to span a distance of 1.75 mm?

Jan 27th, 2015

1pm=10^-12 m

124pm=124x10^-12 m

1.75mm=1.75x10^-3m

So 1.75mm/(2x124pm)=1.75x10^-3m/(2x124x10^-12 m)

                               =0.00706x10^9

                               =7.06x10^6

So 7.06x10^6 iron atoms would have to be laid side by side to span a distance of 1.75 mm

Jan 27th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Jan 27th, 2015
...
Jan 27th, 2015
Sep 20th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer