Through (−9, 6)parallel to the line x = 1
Through (2, 7); perpendicular to the line y = 6
(−1, −3);perpendicular to the line 2x + 7y + 9 = 0
perpendicular to the line
1. Lint through (-9,6) and parallel to x=1 is
y-y1 = m ( x-x1). So y-6 =1(x+9). Because its slope is
y-6 = x+9
2. Slope is 0 so y-7 = 0.
The eq. y= 7
3. 2x+3y+9= 0 has slope. -2
aline perpendicular has inverse negative slope so its slope is +1/2
The equation is: (y+3) = 1/2 ( x+1)
y+3 = 1/2x +1/2
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