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Find an equation of the line that satisfies the given conditions.

label Algebra
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schedule 0 Hours
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Through (38);  parallel to the line passing through (46) and (02)

Through (−4−12);perpendicular to the line passing through (−10) and (3−2)

Jan 27th, 2015

Plug (4,6)(0,2)into y=ax+b

2=b

6=4a+b

Since b=2, 6=4a+2,4a=-4, a=-1

The equation of parallel line is y=-1x+2

Since equation you want is parallel to this line, they share the same "a"

y=-1x+b

Plug (3,8) into the equation

8=-3+b

b=11

Thus, your equation is y= -1x+11

Jan 27th, 2015

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Jan 27th, 2015
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Jan 27th, 2015
Sep 23rd, 2017
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