A chemist takes 6.0 L of 3.5 KOH and dilutes its to make 12.5 L. What is the new concentration of the diluted KOH?

let C1 represent the initial concentration and V1 the initial volume let let C2 represent the final concentration and V2 the final volume

CIVI=C2V2

6*3.5=12.5*V2

WHEN YOU DIVIDE BOTH SIDES BY12.5,

V2=1.68M

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