A 2989 kg car moves down a level highway
under the acceleration of two forces. One is
1182 N forward force expected on the drive
while by the road; the other is 901 N resistive
force. Answer in units of m/s
Please note that, since the two forces are opposite each other, then the magnitude a of the acceleration of your car, is:
Since your car has traveled a distance d, I can apply this formula:
d= (1/2) a* t^2,
where t is the time needed to our car to travel that distance d.
From the last formula, I get t as below:
then I substitute into the formula which gives the speed v reachd by our car, namely:
v = a*t =a* sqrt[(2d)/a], so
v=sqrt (2 d a)
using your numerical dat, we get:
v= sqrt(2*0.094*25)=2.17 m/sec
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?