algebra question help.docx

Question 1)

Please note that the slope of your line is m=7, so the slope m' of the requested line has to be m'=-1/7.

Now I apply this equation:

y-y_1=m'(x-x_1)

where (x_1,y_1) is your point, namely (-8,-6). So I can write:

y-(-6)=(-1/7) (x-(-8))

y+6= -x/7 -8/7

so:

7y+42=-x-8, and finally:

x+7y+50=0

Question 2)

here we have to apply the same equation before, and this time, note that m'=7 since parallel lines have to have the same slope.

So I can write:

y+6=7(x+8)=7x+56

then:

y=7x+50

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