HOW DO YOU SOLVE CONIC SYSTEMS FOR ALGEBRA 2? X^2/3 - (Y+2)^2/4=1; X^2=Y^2/11

From second equation you get x = 0.3 y

Substitute the x value in the first equation and simplify, you get y^2 + 4.54 y +24 =0

Solve for y and you will find that no real solution for y exist. However, imaginary roots involving I exist.

Answer: real solution does not exist

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