since the slope M of your line is M=-3, then the requested line has to have a slope M' equal to 1/3.
Then the requested equation is:
y - 5 = (1/3) (x+5)
and after simplification, I get:
x-3y+20 = 0.
here the slope M' has to be M' = -3, since parallel line have same slope. The the requested equation is:
y - 5 = (-3) ( x+5)
and after a simplification, I can write:
y = - 3x -10
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