Algebra question explain

label Algebra
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Jan 28th, 2015

Question 1)

since the slope M of your line is M=-3, then the requested line has to have a slope M' equal to 1/3.

Then the requested equation is:

y - 5 = (1/3) (x+5)

and after simplification, I get:

x-3y+20 = 0.


Question 2)

here the slope M' has to be M' = -3, since parallel line have same slope. The the requested equation is:

y - 5 = (-3) ( x+5)

and after a simplification, I can write:

y = - 3x -10

Jan 28th, 2015

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Jan 28th, 2015
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Jan 28th, 2015
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