Chemistry conversion

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If a chemist titrates 125 mL of sodium hydroxide with a 6.2 M solution of hydrochloric acid and the titraiton requires 65.0 mL of the acid to reach the end point. What is the concentration of the sodium hydroxide?

Jan 28th, 2015

BALANCE equation
NaOH + HCl --> NaCl + H2O

CALCULATE number of moles of HCl present
65.0 mL HCl x 1 L/1000 mL x 6.2 mol HCl/ 1 HCl = .031 mol HCl

USE MOLAR RATIO from equation to convert from moles of HCl to moles of NaOH
.031 mol HCl x 1 mol NaOH/1 mol HCl = .031 mol NaOH

CALCULATE concentration
Concentration = number of moles/volume
Volume of NaOH = 125 mL = .125 L
.031 mol NaOH/.125 L NaOH
Concentration = .248 mol/L = .248 M

Jan 28th, 2015

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