…from ground level with an initial velocity of v and angle theta is x=1/32 v^2 sin 2theta. Find the distance traveled if the initial velocity is 50 feet per second and cos theta is radical 3/2.

cos Q = sqrt(3)/2 ---> sinQ = 1/2sin2Q = 2sinQcosQ = 2*1/2*cosQ = sqrt(3)/2

x = 1/32 *50^2*sqrt(3)/2

=2500/64*sqrt(3)=67.66 ft

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