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The horizontal distance d in meters that a projectile will travel in the air...

label Calculus
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schedule 0 Hours
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before returning to height from which began is described by the initial velocity of the projectile vo, angle of elevation theta, and acceleration due to gravity g in equation d = vo^2sin2theta/g. If g=9.8 m/s^2 & velocity=34 m/s^. Determine d.

Jan 28th, 2015

With the given equation d = vo^2sin2theta/g, and the provided information g=9.8 m/s^2; velocity=34 m/s, there are still two unknowns: theta and d. It is therefore, unsolvable. 

The results would be d= (34*sins(theta))/9.8 

If the value for theta were provided, then the problem could be fully solved. 

Jan 29th, 2015

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Jan 28th, 2015
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Jan 28th, 2015
Sep 20th, 2017
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