4. The molar ration between O2 and NH3 is 3:4. So when 3.0 moles of NH3 are reacted, 3.0*3/4=2.25 moles of O2 are needed.
So the answer is b
5. The mole of CO2=86.7/44=1.97 mol
When 25.0g or 25.0/12=2.08 moles of C are completely reacted, 2.08 moles of CO2 could be produced.
So the yield = 1.97/2.08*100%=94.7%
The answer is b
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