x^{2} + y^{3} − x^{2}y^{2} = 64

For the x-intercepts set y = 0

x^2 + (0)^3 - (x^2)(0^3) = 64

x^2 = 64

x = +/-8

Therefore the x-intercepts are (-8,0) and (8,0)

For the y-intercepts, set x = 0

0^2 + y^3 - (0^2)(y^3) = 64

y^3 = 64

y = 4

Therefore the y-intercept is (0,4)

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up