Need help calculating data table

Chemistry
Tutor: None Selected Time limit: 1 Day

Jan 29th, 2015

mass of magnesium0. reacted40.73g-40.46g=0.27g
moles of magnesium reactedmass/RMM=0.27/24=0.01125
mass oproductmole ratio is 2:1:2,thus the moles of MgO =0.01125
mass of MgO=moles *the RMM of MgO
0.01125*40=0.45g
mass of oxygen reacted40.91g-40.73g=0.18g
moles of oxygen reactedmoles =mass/RMM
moles=0.18/16=0.01125
experimental molar ratio Mg:O1:1
accepted molar ratio2:1
percentage error(accepted number  of moles-experimental number of moles)/accepted number of moles*100% = 0.01125-0.005625)/0.01125*100%=50%


Jan 29th, 2015

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Jan 29th, 2015
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Jan 29th, 2015
Dec 4th, 2016
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