timer Asked: Apr 29th, 2017
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Question Description

Eyiafiallajokull is a volcano in Iceland.

During a recent eruption, the volcano spewed out copious amounts of ash.

One small piece of ash was ejected from the volcano with an ininitial velocity of 368 ft/sec.

The height H, in feet, of our ash projectile is given by the equation:

H = -16ft^2 + 368t,

where t is the time, in seconds.

The graph of this equation will be parabola.

We will assume that the volcano has no height.

i.e H = 0 at t = 0.

Question 1)

When does the ash projectile read its maximum height?

Question 2)

What is its maximum height?

Question 3)

When does the ash projectile return to the ground?

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Tutor Answer

School: UC Berkeley

The solution is ready.

𝐻(𝑡) = −16𝑡 2 + 368𝑡 = 16𝑡(23 − 𝑡).

1. The graph is a parabola branches...

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awesome work thanks

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