Then describe the solution

1) 7x+3=6(x-2)

2) 3-5.2p=-5.2p+3

3) 2(q+3)=4q+q-9

Find the solution if is possible on the next 3

1) 4p-6=8+2p 2) 2k-9=-8 3)2(x+2)-3=2x+1

7x+3 = 12x-12

7x-12x=-12-3

-5x= -15

x =3

True for x=3 ; only one solution

3-5.2p = -5.2p+3

-5.2p+3 =-5.2p+3

This is true for all values of p ; infinite number of solutions

2q+6 = 5q-9

2q-5q =-9 -6 =-15

-3q = -15

q =5 ; Only one solution

4p-6 = 8+2p

4p-2p = 8+6=14

2p =14

p =14/2 =7

2k-9 = -8

2k = -8+9 =1

k =1/2 or 0.5

2x+4-3=2x+1

2x+1 = 2x+1

This is an identity. It is true for all values of x. Infinite number of solutions

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