Chem Stoic question

Chemistry
Tutor: None Selected Time limit: 1 Day

Cl2+2Na=2NaCl

How do I find excess reactant 4.00 g cl2 and 17.00 g 2NA

Jan 30th, 2015

          Cl2 +             2Na = 2NaCl

 2*34.45=69         2*23=46

4                          x

4/69 = x/46

x= 4*46/69 = 2.67 g

excess Na = 17.00-2.67 = 14.33 g

Jan 30th, 2015

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