specific heat of a metal, physics assignment help

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I need Physics LAB report, every thing you need to know in files.

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PHYS 164 LAB #13 Specific Heat of a Metal ANALYSIS Calculation of Specific Heats and Uncertainties Identify the type of metal in the appropriate cell Lead METAL 1: cx = 0.036 cal/g-oC cx(Hi) = 0.047 cal/g-oC cx(Lo) = 0.024 cal/g-oC cx = 0.036 cal/g-oC ± Steel METAL 2: cx = 0.130 cal/g-oC cx(Hi) = 0.140 cal/g-oC cx(Lo) = 0.118 cal/g-oC cx = 0.130 cal/g-oC ± Aluminum METAL 3: cx = 0.232 cal/g-oC cx(Hi) = 0.265 cal/g-oC cx(Lo) = 0.192 cal/g-oC cx = 0.232 cal/g-oC ± TABLE I. Summary of Results Metal Lead Aluminum Steel cexp 0.036 0.232 0.130 ± cacc 0.031 0.22 0.118 ± 0.001 0.01 0.001 % diff 15.9 5.3 9.7 Agree? Yes Yes Yes PHYS 164 LAB #13 Specific Heat of a Metal DATA PRELIMINARY DATA TR = 23 ± 0.5 mc = 41.1 ± 0.1 cc = 0.22 ± 0.01 METAL 1: o Room Temperature C g Mass of Calorimeter o cal/g- C Specific Heat of Aluminum Steel Temperatures (oC) Tx = 95 Masses (g) mx = 251 ± 0.10 m(c+w) = 210 ± 0.20 Tw = * mw = 168.9 ± 0.20 Te = METAL 2: ± 5 24 ± 1 35 ± 1 Temperatures (oC) Tx = 95 ± 5 Lead Masses (g) mx = 351.6 ± 0.10 m(c+w) = 200.7 ± 0.20 Tw = 24 ± 1 * mw = 159.6 ± 0.20 Te = 29 ± 1 Temperatures (oC) Tx = 95 METAL 3: Aluminum Masses (g) mx = 90.3 ± 0.10 ± 5 m(c+w) = 197 ± 0.20 Tw = 24 ± 1 * mw = 155.9 ± 0.20 Te = 32 ± 1 * Calculate mw after the experiment has been performed from mw = m(c+w) - mc ...
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markjunior209
School: UC Berkeley

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Physics LAB report

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Names of lab partners
1. …………………..
2. …………………..
3. …………………..
4. …………………..

Experiment 12; specific heat of a metal

Introduction
a. Objective
The objective of this experiment is to learn what specific heat is and how it differs for various
metals.
b. Procedure
1. Fill the boiler about one-third full of water and start heating it with the cover off.
2. Weigh the (empty) inner vessel of the calorimeter (without the fiber ring but with the
stirrer). Record the material of the calorimeter.
3. Write down the name of each me...

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