Intermediate Algebra: Extra Credit , algebra homework help

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xuhag87

Mathematics

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MUST GIVE STEP BY STEP ANSWER. SHOW ALL WORK!! DETAILED WORK IS BEST!!

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Explanation & Answer

The solutions are ready. Please ask if something is unclear or if your need more details.There are two uncertainties in the conditions, I marked them with yellow. Answer to these questions and I'll re-solve if needed. docx and pdf files are identical

3

3

1. (2π‘₯ + 3)2 = 27. Note that 2π‘₯ + 3 must be non-negative, i.e. π‘₯ β‰₯ βˆ’ 2. Now we can
raise both sides to the power
((2π‘₯ +

2
3 3
3)2 )

2
3

and obtain an equivalent equation:
2

2

= 2π‘₯ + 3 = 273 = (33 )3 = 32 = 9, 2π‘₯ = 9 βˆ’ 3 = 6, π‘₯ =

6
= πŸ‘.
2

3

This 𝒙 = πŸ‘ β‰₯ βˆ’ 2 and thus is the only solution. Or you need complex solutions, too?

2. 𝑦 4 βˆ’ 40𝑦 2 + 144 = 0. Denote π‘₯ = 𝑦 2 , then π‘₯ 2 βˆ’ 40π‘₯ + 144 = 0.
Use the quadratic formula for an even 𝑏:
π‘₯ = 20 Β± √202 βˆ’ 144 = 20 Β± √256 = 20 Β± 16 = 4; 36.
Now solve 𝑦 2 = 4 or 𝑦 2 = 36 and obtain four roots: βˆ’πŸ, 𝟐, βˆ’πŸ”, πŸ”.

3. (8𝑛 βˆ’ 3)(7𝑛2 + 5π...


Anonymous
I was having a hard time with this subject, and this was a great help.

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