Maths help urgent needed

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If x^2+y^2=51xy

Prove :

log (x-y)/7=1/2 log xy

Feb 1st, 2015

x^2+y^2=51xy or x^2+y^2-2xy=51xy-2xy or (x-y)^2=49xy or x-y=7xy^1/2 or (x-y)/7=xy^1/2 or log (x-y)/7=1/2logxy

Feb 1st, 2015

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