If x^2+y^2=51xy

Prove :

log (x-y)/7=1/2 log xy

x^2+y^2=51xy or x^2+y^2-2xy=51xy-2xy or (x-y)^2=49xy or x-y=7xy^1/2 or (x-y)/7=xy^1/2 or log (x-y)/7=1/2logxy

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up