Description
Show that the equation represents a circle by rewriting it in standard form, and find the center and radius of the circle.
x2 + y2 − 2x + 8y + 16 = 0
standard form | ||
center | (x, y) = ( | ) |
radius |
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Explanation & Answer
Re-organization the equation putting x and y terms together:
x^2 - 2x + y^2 + 8y = -16
(x -1)^2 + (y+4)^2 = -16 +1 + 16
therefore, (x - 1)^2 + (y+4)^ = 1
center is (1,-4) radius is 1
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