Through(1, −4);parallel to the line x + 2y = 6

Through (−1, −2);perpendicular to the line 2x + 5y + 7 = 0

Through (0, 7); parallel to the line passing through (1, 5) and (−3, 1)

1. first get slope of line: 2y = -x + 6, y = -1/2x + 3, so slope = -1/2

Now use the point/slope formula

y -(-4) = -1/2(x - 1)

y+4 = -1/2x+1/2

y = -1/2x - 7/2

2. 5y = -2x - 7

y = -2/5x - 7/5 so the slope is -2/5

the negative reciprocal of -2/5 is 5/2

y+2 = 5/2(x+1)

y+2 = 5/2x+5/2

y = 5/2x+1/2

3. slope = 1-5 / -3-1 = -4/-4 = -1

y-7 = -1(x-0)

y = -x+7

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up