math question.............please do this asap

label Mathematics
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Feb 3rd, 2015

f(x) = x^2 - 4x

A.R.C = f(b) - f(a) / b - a

x = 3 = a         x = 5 = b

f(b) = b^2 - 4b   ==========> f(5) = 5^2 - 4(5) = 25 - 20 = 5

f(a) = a^2 - 4a   ==========> f(3) = 3^2 - 4(3) = 9 - 12 = - 3

Now 

A.R.C = f(b) - f(a) / b - a

           = 5 - (- 3) / 5 - 3

           = 5 + 3 / 2

           = 8 / 2

           = 4

Hence    A.R.C = 4

Feb 3rd, 2015

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Feb 3rd, 2015
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Feb 3rd, 2015
Jun 22nd, 2017
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