What is the molality of a solution of 10.0 g Ag(ClO3) in 201 g water?
molality = moles solute/kg solvent
10.0 g Ag(ClO3) in 201 g water
Ag(ClO3) is a solute
moles solute = mass solute / molecular weight solute
molecular weight of Ag(ClO3) = 108 + 35.5 + (16x3) = 191.5 g/mol
moles solute = 10 g / 191.5 g/mol = 0.052 moles
201 g of water = 0.201 kg
molality = 0.052 moles / 0.201 kg = 0.26 mol/kg
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