What is the equilibrium constant for the following reaction?

Follow these steps : 2CO (g) + O2 (g) ---->. 2CO2 (g). call it eq. 1

C (graphite) + 1/2 O2 (g) -----> CO (g) call it eq.2

C (graphite) + O2 -------> CO2 (g). call it eq 3

Now multiply sq. 2 by2 band add to sq. 1

You get 2 C (graphite) + 2 O2 (g) -----> 2CO2

Divide by 2 and you get C (graphite) + O2 -------> CO2

k1 = [CO2]^2/ [CO]^2 [O2]. And k2 = [CO]/ [C graph][O2]^1/2

And 2k2 = [CO]^2/ [Cgr]^2 [O2}

So k overall =. sqrt ( k1 x 2k2)

= sqrt ( 3.01 x 10^91 multiplied by 2 x 2.28 10^23

k overall =. sqrt ( 13.7 x 10^ 114)

= 3.7 x 10^ 57

Answer: equilibrium constant for eq. 3 = 3.7 x 10 ^ 57

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