The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and

Chemistry
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The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is

A.2.05 gram
B.3.05 gram
C.4.05 gram
D.5.05 gram

Feb 4th, 2015

3.05 gram

Balance chemical equation
P4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g

Here limiting reagent is P4.

124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g

Feb 4th, 2015

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