The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

The mass of P4O10 that will be obtained from the reaction of 1.33 gram of P4 and 5.07 of oxygen is

A.2.05 gram
B.3.05 gram
C.4.05 gram
D.5.05 gram

Feb 4th, 2015

3.05 gram

Balance chemical equation
P4 + 5 O2 -> P4O10
1 mol 5 mol 1 mol
124g 160g 284g

Here limiting reagent is P4.

124g of P4 produce P4O10 = 284g
So, 1.33g of P4 produce P4O10 = (284/124)*1.33 = 3.05g

Feb 4th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Feb 4th, 2015
...
Feb 4th, 2015
Jun 28th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer