You find a Moon 2 with a smaller orbit. Which of Kepler's laws can you apply to find its period of revolution and explain how you would do it. Would Moon 2's period be larger or smaller than Moon 1's

You would use Keppler's 3rd Law, which states that the square of the period is proportional to the cube of its semi-major axis. You can set up a equivalent proportion between period squared and semi-major axis cubed using this fact. Thus, the farther away a planet, or in this case, a moon, the longer the period. Thus, Moon 2's orbit would be smaller than Moon 1's orbit.