You would use Keppler's 3rd Law, which states that the square of the period is proportional to the cube of its semi-major axis. You can set up a equivalent proportion between period squared and semi-major axis cubed using this fact. Thus, the farther away a planet, or in this case, a moon, the longer the period. Thus, Moon 2's orbit would be smaller than Moon 1's orbit.
Feb 5th, 2015
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