If 10.8 kg of A12O3(s), 58.4 kg of NaOH(l) and 58.4 kg of HF(g) react completely, how many kg of cryolite will be produced?
Al2)3(s) + 6NaOH(l) +12HF(g) -> 2Na3AlF6+ 9H2O(g)
given the reaction equation, the mole ratio of Al2O3 to Na3AlF6 is 1:2
we find moles of Al2O3 reacted =mass reacted/molecular mass
molecular mass of Al2O3 is 0.10196Kg/mol
moles of Na3AlF6 using the mole ratio is 2*105.92=211.85moles
mass produced=molecular mass of Na3AlF6*number of moles produced
molecular mass is 0.2099Kg/mol
mass produced =0.2099*211.85=44.47Kg
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