Evaluate the function at the indicated values. (If an answer is undefined, enter

Algebra
Tutor: None Selected Time limit: 1 Day

Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.)

f(x) = x3 + 2x

f(−2)       =             

f(1)         =             

f(0)         =             

f(1/3)=  

f(0.2)     =           

Feb 9th, 2015

f(x) = x3 + 2x

f(−2)  = (-2)^3 + 2*(-2)=-8-4=-12  

f(1)  =1^3 + 2*1=1+2=3    

f(0)  = 0^3 + 2*0=0   

f(1/3)=(1/3)^3 + 2*1/3=1/27+2/3=1/27+18/27=19/27

f(0.2)  = 0.2^3 + 2*0.2=0.008+0.4=0.408         


Feb 9th, 2015

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