Calculate [H^{+}] for a 1.10×10^{-3} M aqueous solution of n-butyric acid (HC_{4}H_{7}O_{2}; K_{a} = 1.50×10^{-5}).

Calculate the pH of the above solution.

1.5e-5 = x^2/ 1.1e-3 -x

x^2 = 1.65e-8 - 1.5e-5x

x^2 + 1.5e-5x - 1.65e-8 = 0

Solve via quadratic equation

x = 0.000121

pH = - log (0.000121) = 3.92

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