Calculate [H+] for a 1.10×10-3 M aqueous solution of n-butyric acid (HC4H7O2; Ka = 1.50×10-5).
Calculate the pH of the above solution.
1.5e-5 = x^2/ 1.1e-3 -x
x^2 = 1.65e-8 - 1.5e-5x
x^2 + 1.5e-5x - 1.65e-8 = 0
Solve via quadratic equation
x = 0.000121
pH = - log (0.000121) = 3.92
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