An aqueous solution of a monoprotic acid HA (Ka = 1.45×10-1) has a pH of 4.75.
pH = 4.75
[H+] =10 ^ -4.75 = 1.78e-5
1.45e-1 M -2.581e-6 = 3.1684e-10
M = 1.78e-5M
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