##### find probability.... around 2 dec

label Statistics
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

p(a)=.66 p(b)=.31 (a upside down u b)=.21

a. p(a\b)

b. p(a upside down u b)

c. P(a upside down u b)c)

Oct 20th, 2017

a. p(a/b) = P( a n b)/p(a) = 0.21/0.66 =

b. p(a upside down u b) is already given, i think you typed it wrong here.

Feb 10th, 2015

My apologies

B. P(a u b)

C. P(a u b)c)

Feb 10th, 2015

sorry but you do not even appreciate the help you are getting by simply besting an answer. I don't see any point in helping you :(

Feb 10th, 2015

Are we getting .32 for part A!

Feb 10th, 2015

yes!

Feb 10th, 2015

It won't cost you anything to select and answer as best, but you still don't do it..
Sorry but I cannot help you, if you dont appreciate my help.

Feb 10th, 2015

I'm sorry u feel that way.....I do appreciate your help...I'm new to this cite....it will take time for me me to understand what I need to do when choosing a best answer....thank you

Feb 10th, 2015

I will select.....now that I know that's what I need to do...thanks

Feb 10th, 2015

Feb 10th, 2015

B. P(a u b) = P(a) + p(b) - p(a n b) = .66 +.31 - .21 = .76

Feb 10th, 2015

Thank you for part a and b......no problem on c....you have been a great help

Feb 10th, 2015

can you please check this one as well...

https://www.studypool.com/free/160495/find-probability-of-independent-and-mutually-exclusive

Feb 10th, 2015

c. P(AUB)c=1-P(AUB)= 1 - .76 = 0.24

Feb 11th, 2015

...
Oct 20th, 2017
...
Oct 20th, 2017
Oct 21st, 2017
check_circle