a. length of field inside road= 500-2x

width= 300-2x

b . Area= {500-2x}{300-2x} or

4x^2-1600x+150000 quadratic function

c. x=5 then area= (300-10)(500-10)= 290×490

Similarly x=10 area=(300-20)(500-20) = 280×480

...

E.for this you can equate area obtained at b to half of the total area I.e. (500x300)

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