An aqueous solution contains 3.75%
(ammonia) by mass. The density of the aqueous ammonia is 0.979g/mL.
What is the molarity of NH3
in the solution? please show work so I understand how to do it. :) thank you.
So in 1ml solution, the mass of the aqueous solution is 0.979g.
Then the mass of ammonia=0.979*3.75%=0.0367 g
The molar mass of ammonia=14+3=17 g/mol
So the molarity of NH3=(0.0367/17 mol)/1ml=0.00216 mol/ml=2.16 mol/L
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